[QUOTE 2505306, member: 9609"]I was checking the calibration of a torque wrench, which (i think) is quite straight forward. Hold wrench in vice, add weight until click, calculate weight and distance and check against setting.
Now not that the following makes any real difference, but I wanted to improve my accuracy by including the weight of the wrench in my calculations. But not really sure how to do this.
Length = 466mm
Turning point 25mm form end (a)
(CoG) centre of gravity230mm from end (a) {205mm from turning point}
weight of wrench =1250g
So with the turning point held in a vice, and the wrench parallel to the ground, what torque is being applied at the vice.
Lets ignore the fact that when the setting is changed the wrench becomes longer. And lets ignore the 25mm sticking out the other side of the turning point
I was thinking half the weight x distance from turning point to CoG
0.205*0.625 = 0.128kg/metres (0.92 lb/feet)
I will give
@thom a shout, but I'm sure others will be able to explain how I should be calculating the effect of the wrench its self.[/quote]
Why half the weight ? I reckon you just need to add the full weight of the wrench multiplied by the distance from the COG to the centre of rotation of the wrench/turning point.