What's An Acceptable Number?

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Vidor06

Long term loafer
If you open a new packet of Hob Nobs or McVities Chocolate Homewheat, whats an acceptable number to take? Equally whats the highest number you have taken at one sitting. Other buscuits are suitable substitutes.
I try to restrict myself to 2 but quite often find myself taking a third. I think the most I've ever gone through in one go is 4.
On a similar vein, if someone offers you their bag of crisps, do you only ever take one or is it ok to take a few? Or is everyone else on here disciplined cycling machines?
Finally a wee anecdote to finish. We were playing in a rugby tourney and the only people fed afterwards were the refs and the touring teams. My mate, a ref, sat down beside me and a few team mates with his plate of sausage and chips. He offered the table some food. I took a couple of chips but the 2 guys beside me reached over and took both the sausages. Funny to watch but Im sure it wasnt so funny to be on the receiving end.
 

martint235

Dog on a bike
Location
Welling
Easy. If I open a packet of HobNobs the acceptable number to take is equal to and not less than the number of HobNobs in the packet.

If someone else opens a packet then x=N-2 where N is the number of biscuits in the packet (-2 as I don't want to come across as greedy)
 

EltonFrog

Legendary Member
Easy. If I open a packet of HobNobs the acceptable number to take is equal to and not less than the number of HobNobs in the packet.

If someone else opens a packet then x=N-2 where N is the number of biscuits in the packet (-2 as I don't want to come across as greedy)

This is correct, but a mug of tea has to be in the equation somewhere.
 

jonny jeez

Legendary Member
This is correct, but a mug of tea has to be in the equation somewhere.
True
N=X-2 over V (v equals volume of tea)

But then we need to add temperature of tea as many a hob nob can be squared away while waiting for tea to reach optimum dunking temperature.
So if falling temperature is represented as h over t (t equals time)

We get

N=X-2
------------------
V x ( H
----
T)

Sounds right.
 

martint235

Dog on a bike
Location
Welling
True
N=X-2 over V (v equals volume of tea)

But then we need to add temperature of tea as many a hob nob can be squared away while waiting for tea to reach optimum dunking temperature.
So if falling temperature is represented as h over t (t equals time)

We get

N=X-2
------------------
V x ( H
----
T)

Sounds right.
Can't stand tea.
 

jonny jeez

Legendary Member
Can't stand tea.
Oh...er...well I'm afraid there is no hope for you.

You could replace V for Cp (cappuccino) but i fear that all starts to sound a little unnatural.
 

Salad Dodger

Legendary Member
Location
Kent Coast
I would try to restrict myself to 2 biscuits. Sometimes this strategy works. Sometimes it fails, and then 3 or even 4 may be consumed.

They dont call me Salad Dodger for nothing!
 
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