Are you smarter than an 11 year old, Q1?

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AlanW

Legendary Member
Location
Not to sure?
Five friends meet to play tennis.
There is only one court, and they want it to be as fair as possible.
Can you arrange a playing schedule so that they can each play exactly three other opponents?
 

thomas

the tank engine
Location
Woking/Norwich
The answer is no to at least one of your two questions. Either it isn't possible, or I'm not as smart as an 11 year old :angry:
 

ttcycle

Cycling Excusiast
I think this is correct- if they play two players:

A B C D E are the players:

A vs B
C vs D
E vs A
B vs C
D vs E
D vs B
A vs C
E vs B
 

summerdays

Cycling in the sun
Location
Bristol
What about each person plays one game of singles and one game of doubles ...? Then they have all played 3 opponents?

Edit : no I dont' think that works....

What about that game we played as a kid where we ran around the court from end to end taking it in turns....
 

ttcycle

Cycling Excusiast
Yep Thomas I noticed when I posted it so that doesn't work

Summerdays might have the right answer
 
No.
5 x 3 = 15, and you need two people per match, so in the schedule there are 15 half-matches. So one player will be unpaired.

Why can't they do as in the Monty Python sketch*, play doubles with three players on one side? Pace John Cleese...:angry:

*at about 1:40
 

thomas

the tank engine
Location
Woking/Norwich
ttcycle said:
Yep Thomas I noticed when I posted it so that doesn't work

Summerdays might have the right answer


I don't think so... i swear someone has to get left out because of odd and even numbers???
 

ttcycle

Cycling Excusiast
That's right- I'm lost - I was actually speaking to a CCer about maths being the subject I disliked the most today- quite a logical thinker but not in the maths sense - I don't remember learning any of this stuff at school...!!

I know some really good visual questions that I'm much better at- just don't know where to find the images- might draw it out and take a photo and post up instead.
 

potsy

Rambler
Location
My Armchair
summerdays said:
What about each person plays one game of singles and one game of doubles ...? Then they have all played 3 opponents?

Edit : no I dont' think that works....

What about that game we played as a kid where we ran around the court from end to end taking it in turns....
Sounds right to me SD,1 game of doubles so each person is playing against 2 opponents,then 2 games of singles where each player plays their doubles partner=3 opponents all in.:angry:
 
OP
OP
AlanW

AlanW

Legendary Member
Location
Not to sure?
thomas said:
The answer is no to at least one of your two questions. Either it isn't possible, or I'm not as smart as an 11 year old :laugh:

Well I have spent over an hour trying to figure it out before I asked on here, and I don't think that it can be done either. :angry:

In case you had not guessed, this is my daughters homework!
 

rich p

ridiculous old lush
Location
Brighton
AlanW said:
Well I have spent over an hour trying to figure it out before I asked on here, and I don't think that it can be done either. :angry:

In case you had not guessed, this is my daughters homework!

I read there was a lot of cheating going on in exams these days. I feel implicated now!
 

Bman

Guru
Location
Herts.
How about:

Play 5 games of doubles. 1 person sits out each game.

2&3vs4&5 1 sits out
1&3vs4&5 2 sits out
1&2vs4&5 3 sits out
1&2vs3&5 4 sits out
1&2vs3&4 5 sits out
 
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