asterix
Comrade Member
- Location
- Limoges or York
Sounds like the kind of stuff that would be discussed at the world's most boring dinner party.
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To which
Sounds like the kind of stuff that would be discussed at the world's most boring dinner party.
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He's got you bang to rights Darth. I'll say no more![]()
Sounds like the kind of stuff that would be discussed at the world's most boring dinner party.
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Boring? - No, Bloody difficult to understand - Yes - but I could be applying that to my bicycle parts and frame combination / speculation posts as well
I understand Al - and suitable fixed for you!![]()
Yeah, you're cards marked big fella, Marin's going to be doing some trajectory and impact calculations for me, just right for taking down a large person!
Yeah, you're cards marked big fella, Marin's going to be doing some trajectory and impact calculations for me, just right for taking down a large person!
Something doesn't quite add up here...Dan posts once and it is multiplied by four and Rich is a =1= 4/3 pies are too much - even for Vernon!![]()
I slept like a log last night and woke up inthegrate.
fook i used to be able to do these in my sleepabout 23yrs ago
In fact I`ve just been reaquanting myself with trigonometry since my wife started her Uni course!![]()
(d ((Log[1 - I x] + Log[1 + I x]) Log[x] + PolyLog[2, -I x] + PolyLog[2, I x])) / 2
Sorry all - been elsewhere since I posted.
Err - Yes. I got that too from Mathematica. But it's from an undergraduate science course and I'm pretty sure PolyLogs are not in the syllabus.
D'oh. An easier substitution is z=x. Residue theorem. Integrate around the simple pole z=i. If you can't do it I'll write something up later.
Just use the principal logarithm value ln(i) = πi/2. Use some contour that makes sense and doesn't muck it up. Set all bits of this equal to the value from the residue theorem. Strip out whichever bit you want. Take real/imaginary parts as as radius → ∞. As there is no real part in whatever it is you have constructed then the answer is obviously zero!