Integration

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rich p

ridiculous old lush
Location
Brighton
Incidentally, when I'm watching University Challenge the answer is either, 0, 1 or the square root of -1.

If this doesn't help, I'm all out of ideas.
 

threebikesmcginty

Corn Fed Hick...
Location
...on the slake
Yeah, you're cards marked big fella, Marin's going to be doing some trajectory and impact calculations for me, just right for taking down a large person!

MacB Vs Teef - it'll be like the Goliath and Goliath Bible story.
 
OP
OP
twentysix by twentyfive

twentysix by twentyfive

Clinging on tightly
Location
Over the Hill
fook i used to be able to do these in my sleep
ohmy.gif
about 23yrs ago
blush.gif
In fact I`ve just been reaquanting myself with trigonometry since my wife started her Uni course!


(d ((Log[1 - I x] + Log[1 + I x]) Log[x] + PolyLog[2, -I x] + PolyLog[2, I x])) / 2


Sorry all - been elsewhere since I posted.

Err - Yes. I got that too from Mathematica. But it's from an undergraduate science course and I'm pretty sure PolyLogs are not in the syllabus.
 
OP
OP
twentysix by twentyfive

twentysix by twentyfive

Clinging on tightly
Location
Over the Hill
D'oh. An easier substitution is z=x. Residue theorem. Integrate around the simple pole z=i. If you can't do it I'll write something up later.

Just use the principal logarithm value ln(i) = πi/2. Use some contour that makes sense and doesn't muck it up. Set all bits of this equal to the value from the residue theorem. Strip out whichever bit you want. Take real/imaginary parts as as radius → ∞. As there is no real part in whatever it is you have constructed then the answer is obviously zero!

Ah ha marinyork. It has been a very very long time since I've done contour Integration. I'll give that a go. As said above the question is from an undergrad 1st year science course. 1st term too. So I'm not sure they have covered contour integration yet. I shall check.

The lead into the question was show Integral(0->Infinity) Ln[x]/x^2 dx = -Integral (0->1) Ln du which is easy with a substitution of u=1/x. So I wondered if the question was a typo for Ln[x]/(1+x)^2 dx. That one drops out as Zero (the proof asked for) easily using u=1/(1+x). However I've been told I must not alter the question........... I still think that I'm correct about the typo tho'.

So I'm off to brush up on contours.
 
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