Got 4 too. Missing 0,1 and 8
AndyRM XOXO Location North Shields 23 Jan 2015 #1,953 0-markymark-0 said: Got 4 too. Missing 0,1 and 8 Click to expand... I've got 0. Hint? Spoiler Trigonometry.
0-markymark-0 said: Got 4 too. Missing 0,1 and 8 Click to expand... I've got 0. Hint? Spoiler Trigonometry.
M Markymark Guest 23 Jan 2015 #1,954 AndyRM said: I've got 0. Hint? Spoiler Trigonometry. Click to expand... Please!
benb Evidence based cyclist Location Epsom 23 Jan 2015 #1,955 0-markymark-0 said: Ok, got 1 and 8 too but missing 0 Click to expand... If you got 8, which I think is the hardest, you should get 0. Spoiler Assuming you know that 0! (factorial) = 1
0-markymark-0 said: Ok, got 1 and 8 too but missing 0 Click to expand... If you got 8, which I think is the hardest, you should get 0. Spoiler Assuming you know that 0! (factorial) = 1
M Markymark Guest 23 Jan 2015 #1,957 Ok, your clue gave me 0 (never would have got it othersise!) Have the lot now.
benb Evidence based cyclist Location Epsom 23 Jan 2015 #1,958 Spoiler: The solution 0! = 1. That's the key to 0. (0! + 0! + 0!)! = 6 (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 (3 x 3) - 3 = 6 √(4 x 4) + √4 = 6 5 + (5 / 5) = 6 (6 - 6) + 6 = 6 7 - (7 / 7) = 6 (√(8 / 8) + 8)! = 6 (√9 x √9) - √9 = 6 Last edited: 23 Jan 2015
Spoiler: The solution 0! = 1. That's the key to 0. (0! + 0! + 0!)! = 6 (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 (3 x 3) - 3 = 6 √(4 x 4) + √4 = 6 5 + (5 / 5) = 6 (6 - 6) + 6 = 6 7 - (7 / 7) = 6 (√(8 / 8) + 8)! = 6 (√9 x √9) - √9 = 6
M Markymark Guest 23 Jan 2015 #1,959 benb said: Spoiler: The solution 0! = 1. That's the key to 0. (0! + 0! + 0!)! = 6 (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 (3 x 3) - 3 = 6 √(4 +4) + √4 = 6 5 + (5 / 5) = 6 (6 - 6) + 6 = 6 7 - (7 / 7) = 6 (√(8 / 8) + 8)! = 6 (√9 x √9) - √3 = 6 Click to expand... Typo on 4 & 9 but that's how I did all except 0 √(4 x4) + √4 = 6 (√9 x √9) - √9 (cos0 + cos0 + cos0)! but wsa poitned in right directed by AndyRM
benb said: Spoiler: The solution 0! = 1. That's the key to 0. (0! + 0! + 0!)! = 6 (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 (3 x 3) - 3 = 6 √(4 +4) + √4 = 6 5 + (5 / 5) = 6 (6 - 6) + 6 = 6 7 - (7 / 7) = 6 (√(8 / 8) + 8)! = 6 (√9 x √9) - √3 = 6 Click to expand... Typo on 4 & 9 but that's how I did all except 0 √(4 x4) + √4 = 6 (√9 x √9) - √9 (cos0 + cos0 + cos0)! but wsa poitned in right directed by AndyRM
benb Evidence based cyclist Location Epsom 23 Jan 2015 #1,960 0-markymark-0 said: Typo on 4 & 9 but that's how I did all except 0 √(4 x4) + √4 = 6 (√9 x √9) - √9 (cos0 + cos0 + cos0)! but wsa poitned in right directed by AndyRM Click to expand... Oops, thanks, have edited the spoilers.
0-markymark-0 said: Typo on 4 & 9 but that's how I did all except 0 √(4 x4) + √4 = 6 (√9 x √9) - √9 (cos0 + cos0 + cos0)! but wsa poitned in right directed by AndyRM Click to expand... Oops, thanks, have edited the spoilers.
benb Evidence based cyclist Location Epsom 23 Jan 2015 #1,961 4 might in fact be simpler as √4 + √4 + √4
benb Evidence based cyclist Location Epsom 23 Jan 2015 #1,962 A friend sent me a better solution to 8. 8 - √(√(8 + 8)) = 6